(x+2)^2=2(x+6)

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Solution for (x+2)^2=2(x+6) equation: 



(x+2)^2=2(x+6)

We move all terms to the left:

(x+2)^2-(2(x+6))=0



We calculate terms in parentheses: -(2(x+6)), so:

2(x+6)

We multiply parentheses

2x+12

Back to the equation:

-(2x+12)



We get rid of parentheses

(x+2)^2-2x-12=0

We add all the numbers together, and all the variables

-2x+(x+2)^2-12=0

We move all terms containing x to the left, all other terms to the right

-2x+(x+2)^2=12

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